Base | Representation |
---|---|
bin | 1001001001111001000110… |
… | …01100111010001101111011 |
3 | 2122021111220010120112212021 |
4 | 10210330203030322031323 |
5 | 10114311444142144344 |
6 | 110452033431255311 |
7 | 4145265324143614 |
oct | 444744314721573 |
9 | 78244803515767 |
10 | 20131102303099 |
11 | 6461609484867 |
12 | 231166151a537 |
13 | b3047c664608 |
14 | 4d84c9ca4c0b |
15 | 24d9c9887b84 |
hex | 124f2333a37b |
20131102303099 has 2 divisors, whose sum is σ = 20131102303100. Its totient is φ = 20131102303098.
The previous prime is 20131102303087. The next prime is 20131102303111. The reversal of 20131102303099 is 99030320113102.
It is a balanced prime because it is at equal distance from previous prime (20131102303087) and next prime (20131102303111).
It is a cyclic number.
It is not a de Polignac number, because 20131102303099 - 225 = 20131068748667 is a prime.
It is a super-2 number, since 2×201311023030992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20131102303069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065551151549 + 10065551151550.
It is an arithmetic number, because the mean of its divisors is an integer number (10065551151550).
Almost surely, 220131102303099 is an apocalyptic number.
20131102303099 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131102303099 is an equidigital number, since it uses as much as digits as its factorization.
20131102303099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 34.
The spelling of 20131102303099 in words is "twenty trillion, one hundred thirty-one billion, one hundred two million, three hundred three thousand, ninety-nine".
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