201311100130013 has 2 divisors, whose sum is σ = 201311100130014. Its totient is φ = 201311100130012.

The previous prime is 201311100129983. The next prime is 201311100130031. The reversal of 201311100130013 is 310031001113102.

Together with next prime (201311100130031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 154983501882169 + 46327598247844 = 12449237^2 + 6806438^2 .

It is a cyclic number.

It is not a de Polignac number, because 201311100130013 - 2⁸ = 201311100129757 is a prime.

It is a super-2 number, since 2×201311100130013² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201311100129973 and 201311100130000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201311100130213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100655550065006 + 100655550065007.

It is an arithmetic number, because the mean of its divisors is an integer number (100655550065007).

Almost surely, 2^{201311100130013} is an apocalyptic number.

It is an amenable number.

201311100130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

201311100130013 is an equidigital number, since it uses as much as digits as its factorization.

201311100130013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 201311100130013 its reverse (310031001113102), we get a palindrome (511342101243115).

The spelling of 201311100130013 in words is "two hundred one trillion, three hundred eleven billion, one hundred million, one hundred thirty thousand, thirteen".