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201311100130213 is a prime number
BaseRepresentation
bin101101110001011101100100…
…100111001101001110100101
3222101210011010200211112212101
4231301131210213031032211
5202341240113113131323
61552053013115252101
760255150504455653
oct5561354447151645
9871704120745771
10201311100130213
1159164615943677
121a6b353414a031
13884372ac6b7b8
14379d71b4a5dd3
15184186c731dad
hexb717649cd3a5

201311100130213 has 2 divisors, whose sum is σ = 201311100130214. Its totient is φ = 201311100130212.

The previous prime is 201311100130193. The next prime is 201311100130267. The reversal of 201311100130213 is 312031001113102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115926071008609 + 85385029121604 = 10766897^2 + 9240402^2 .

It is a cyclic number.

It is not a de Polignac number, because 201311100130213 - 221 = 201311098033061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201311100130013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100655550065106 + 100655550065107.

It is an arithmetic number, because the mean of its divisors is an integer number (100655550065107).

Almost surely, 2201311100130213 is an apocalyptic number.

It is an amenable number.

201311100130213 is a deficient number, since it is larger than the sum of its proper divisors (1).

201311100130213 is an equidigital number, since it uses as much as digits as its factorization.

201311100130213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 201311100130213 its reverse (312031001113102), we get a palindrome (513342101243315).

The spelling of 201311100130213 in words is "two hundred one trillion, three hundred eleven billion, one hundred million, one hundred thirty thousand, two hundred thirteen".