Base | Representation |
---|---|
bin | 10010101111111010… |
… | …001101001010010111 |
3 | 1220221222021212211221 |
4 | 102233322031022113 |
5 | 312212032441442 |
6 | 13125332111211 |
7 | 1311603603661 |
oct | 225772151227 |
9 | 56858255757 |
10 | 20131140247 |
11 | 85a055a699 |
12 | 3a99a65507 |
13 | 1b8a90240a |
14 | d8d8a1531 |
15 | 7cc522467 |
hex | 4afe8d297 |
20131140247 has 2 divisors, whose sum is σ = 20131140248. Its totient is φ = 20131140246.
The previous prime is 20131140229. The next prime is 20131140259. The reversal of 20131140247 is 74204113102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131140247 - 223 = 20122751639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131180247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065570123 + 10065570124.
It is an arithmetic number, because the mean of its divisors is an integer number (10065570124).
Almost surely, 220131140247 is an apocalyptic number.
20131140247 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131140247 is an equidigital number, since it uses as much as digits as its factorization.
20131140247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 20131140247 its reverse (74204113102), we get a palindrome (94335253349).
The spelling of 20131140247 in words is "twenty billion, one hundred thirty-one million, one hundred forty thousand, two hundred forty-seven".
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