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20131233222013 is a prime number
BaseRepresentation
bin1001001001111001010110…
…00000010100110101111101
32122021112020020220220211221
410210330223000110311331
510114312231201101023
6110452054425313341
74145301504012454
oct444745300246575
978245206826757
1020131233222013
116461676374111
122311699335851
13b304a0812424
144d84dd423b9b
1524d9d60e885d
hex124f2b014d7d

20131233222013 has 2 divisors, whose sum is σ = 20131233222014. Its totient is φ = 20131233222012.

The previous prime is 20131233221977. The next prime is 20131233222041. The reversal of 20131233222013 is 31022233213102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18888393982084 + 1242839239929 = 4346078^2 + 1114827^2 .

It is a cyclic number.

It is not a de Polignac number, because 20131233222013 - 29 = 20131233221501 is a prime.

It is a super-4 number, since 4×201312332220134 (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20131233222043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065616611006 + 10065616611007.

It is an arithmetic number, because the mean of its divisors is an integer number (10065616611007).

Almost surely, 220131233222013 is an apocalyptic number.

It is an amenable number.

20131233222013 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131233222013 is an equidigital number, since it uses as much as digits as its factorization.

20131233222013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 20131233222013 its reverse (31022233213102), we get a palindrome (51153466435115).

The spelling of 20131233222013 in words is "twenty trillion, one hundred thirty-one billion, two hundred thirty-three million, two hundred twenty-two thousand, thirteen".