Base | Representation |
---|---|
bin | 1001001001111001011110… |
… | …00000010101001010111111 |
3 | 2122021112101221012110202021 |
4 | 10210330233000111022333 |
5 | 10114312400341112343 |
6 | 110452105223541011 |
7 | 4145303250312163 |
oct | 444745700251277 |
9 | 78245357173667 |
10 | 20131300332223 |
11 | 6461700240aa3 |
12 | 23116b78ba767 |
13 | b304b16ab802 |
14 | 4d85082d2ca3 |
15 | 24d9dbe530ed |
hex | 124f2f0152bf |
20131300332223 has 2 divisors, whose sum is σ = 20131300332224. Its totient is φ = 20131300332222.
The previous prime is 20131300332131. The next prime is 20131300332239. The reversal of 20131300332223 is 32223300313102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131300332223 - 229 = 20130763461311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131300332023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065650166111 + 10065650166112.
It is an arithmetic number, because the mean of its divisors is an integer number (10065650166112).
Almost surely, 220131300332223 is an apocalyptic number.
20131300332223 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131300332223 is an equidigital number, since it uses as much as digits as its factorization.
20131300332223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 20131300332223 its reverse (32223300313102), we get a palindrome (52354600645325).
The spelling of 20131300332223 in words is "twenty trillion, one hundred thirty-one billion, three hundred million, three hundred thirty-two thousand, two hundred twenty-three".
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