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201313114254103 is a prime number
BaseRepresentation
bin101101110001011111011100…
…101010011110101100010111
3222101210100100001202122102111
4231301133130222132230113
5202341303224222112403
61552053545025051451
760255251432314165
oct5561373452365427
9871710301678374
10201313114254103
1159165459857775
121a6b39b6786b87
13884398c31c797
14379d86cb9a235
15184193948456d
hexb717dca9eb17

201313114254103 has 2 divisors, whose sum is σ = 201313114254104. Its totient is φ = 201313114254102.

The previous prime is 201313114254071. The next prime is 201313114254121. The reversal of 201313114254103 is 301452411313102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201313114254103 - 25 = 201313114254071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201313114234103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656557127051 + 100656557127052.

It is an arithmetic number, because the mean of its divisors is an integer number (100656557127052).

Almost surely, 2201313114254103 is an apocalyptic number.

201313114254103 is a deficient number, since it is larger than the sum of its proper divisors (1).

201313114254103 is an equidigital number, since it uses as much as digits as its factorization.

201313114254103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 201313114254103 its reverse (301452411313102), we get a palindrome (502765525567205).

The spelling of 201313114254103 in words is "two hundred one trillion, three hundred thirteen billion, one hundred fourteen million, two hundred fifty-four thousand, one hundred three".