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20131313101 is a prime number
BaseRepresentation
bin10010101111111010…
…110111010111001101
31220221222121122221221
4102233322313113031
5312212104004401
613125335523341
71311605223634
oct225772672715
956858548857
1020131313101
1185a0668549
123a99b29551
131b8a962cb3
14d8d90851b
157cc5587a1
hex4afeb75cd

20131313101 has 2 divisors, whose sum is σ = 20131313102. Its totient is φ = 20131313100.

The previous prime is 20131313099. The next prime is 20131313161. The reversal of 20131313101 is 10131313102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12493427076 + 7637886025 = 111774^2 + 87395^2 .

It is a cyclic number.

It is not a de Polignac number, because 20131313101 - 21 = 20131313099 is a prime.

Together with 20131313099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20131313161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065656550 + 10065656551.

It is an arithmetic number, because the mean of its divisors is an integer number (10065656551).

Almost surely, 220131313101 is an apocalyptic number.

It is an amenable number.

20131313101 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131313101 is an equidigital number, since it uses as much as digits as its factorization.

20131313101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 20131313101 its reverse (10131313102), we get a palindrome (30262626203).

Subtracting from 20131313101 its reverse (10131313102), we obtain a palindrome (9999999999).

The spelling of 20131313101 in words is "twenty billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred one".