Base | Representation |
---|---|
bin | 1011101101111100110… |
… | …1110101011010001111 |
3 | 201020121212202102102001 |
4 | 2323133031311122033 |
5 | 11244242220111143 |
6 | 232252045413131 |
7 | 20354510006203 |
oct | 2733715653217 |
9 | 636555672361 |
10 | 201313441423 |
11 | 7841620a186 |
12 | 3302356a1a7 |
13 | 15ca3482253 |
14 | 9a5a700b03 |
15 | 538391c14d |
hex | 2edf37568f |
201313441423 has 2 divisors, whose sum is σ = 201313441424. Its totient is φ = 201313441422.
The previous prime is 201313441409. The next prime is 201313441447. The reversal of 201313441423 is 324144313102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201313441423 - 217 = 201313310351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201313441391 and 201313441400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201313441223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656720711 + 100656720712.
It is an arithmetic number, because the mean of its divisors is an integer number (100656720712).
Almost surely, 2201313441423 is an apocalyptic number.
201313441423 is a deficient number, since it is larger than the sum of its proper divisors (1).
201313441423 is an equidigital number, since it uses as much as digits as its factorization.
201313441423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 201313441423 its reverse (324144313102), we get a palindrome (525457754525).
The spelling of 201313441423 in words is "two hundred one billion, three hundred thirteen million, four hundred forty-one thousand, four hundred twenty-three".
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