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20131541 is a prime number
BaseRepresentation
bin100110011001…
…0111011010101
31101212210021122
41030302323111
520123202131
61555253325
7333054353
oct114627325
941783248
1020131541
1110400141
1268aa245
13422b271
1429607d3
151b79d7b
hex1332ed5

20131541 has 2 divisors, whose sum is σ = 20131542. Its totient is φ = 20131540.

The previous prime is 20131523. The next prime is 20131543. The reversal of 20131541 is 14513102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13293316 + 6838225 = 3646^2 + 2615^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20131541 is a prime.

Together with 20131543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20131543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065770 + 10065771.

It is an arithmetic number, because the mean of its divisors is an integer number (10065771).

Almost surely, 220131541 is an apocalyptic number.

It is an amenable number.

20131541 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131541 is an equidigital number, since it uses as much as digits as its factorization.

20131541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 20131541 is about 4486.8185833617. The cubic root of 20131541 is about 272.0355570947.

Adding to 20131541 its reverse (14513102), we get a palindrome (34644643).

The spelling of 20131541 in words is "twenty million, one hundred thirty-one thousand, five hundred forty-one".