Base | Representation |
---|---|
bin | 10010101111111101… |
… | …011111001001010101 |
3 | 1220222000220120200021 |
4 | 102233331133021111 |
5 | 312212243002331 |
6 | 13125402345141 |
7 | 1311614115355 |
oct | 225775371125 |
9 | 56860816607 |
10 | 20132000341 |
11 | 85a0a97912 |
12 | 3a9a1bb1b1 |
13 | 1b8ab43a4b |
14 | d8da46b65 |
15 | 7cc642211 |
hex | 4aff5f255 |
20132000341 has 2 divisors, whose sum is σ = 20132000342. Its totient is φ = 20132000340.
The previous prime is 20132000281. The next prime is 20132000353. The reversal of 20132000341 is 14300023102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18509602500 + 1622397841 = 136050^2 + 40279^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132000341 - 217 = 20131869269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132000381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066000170 + 10066000171.
It is an arithmetic number, because the mean of its divisors is an integer number (10066000171).
Almost surely, 220132000341 is an apocalyptic number.
It is an amenable number.
20132000341 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132000341 is an equidigital number, since it uses as much as digits as its factorization.
20132000341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 20132000341 its reverse (14300023102), we get a palindrome (34432023443).
The spelling of 20132000341 in words is "twenty billion, one hundred thirty-two million, three hundred forty-one", and thus it is an aban number.
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