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201320013400 = 2352117910910627
BaseRepresentation
bin1011101101111110011…
…0111001111001011000
3201020122100010022110121
42323133212321321120
511244300410412100
6232252442323024
720354616610402
oct2733746717130
9636570108417
10201320013400
1178419998870
12330257b9474
1315ca49436ac
149a5b531b72
1553842b951a
hex2edf9b9e58

201320013400 has 192 divisors, whose sum is σ = 521877312000. Its totient is φ = 71610739200.

The previous prime is 201320013371. The next prime is 201320013481. The reversal of 201320013400 is 4310023102.

It is a happy number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 18938887 + ... + 18949513.

It is an arithmetic number, because the mean of its divisors is an integer number (2718111000).

Almost surely, 2201320013400 is an apocalyptic number.

201320013400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201320013400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (260938656000).

201320013400 is an abundant number, since it is smaller than the sum of its proper divisors (320557298600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201320013400 is a wasteful number, since it uses less digits than its factorization.

201320013400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10842 (or 10833 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 201320013400 its reverse (4310023102), we get a palindrome (205630036502).

The spelling of 201320013400 in words is "two hundred one billion, three hundred twenty million, thirteen thousand, four hundred".