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2013211300333 is a prime number
BaseRepresentation
bin11101010010111100101…
…111101001000111101101
321010110110011020102222211
4131102330233221013231
5230441024043102313
64140505001010421
7265310152463452
oct35227457510755
97113404212884
102013211300333
11706886327312
12286210483a11
13117aca648a4c
146d6232dd829
153757cc6be3d
hex1d4bcbe91ed

2013211300333 has 2 divisors, whose sum is σ = 2013211300334. Its totient is φ = 2013211300332.

The previous prime is 2013211300301. The next prime is 2013211300339. The reversal of 2013211300333 is 3330031123102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1808331046564 + 204880253769 = 1344742^2 + 452637^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013211300333 - 25 = 2013211300301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013211300339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006605650166 + 1006605650167.

It is an arithmetic number, because the mean of its divisors is an integer number (1006605650167).

Almost surely, 22013211300333 is an apocalyptic number.

It is an amenable number.

2013211300333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013211300333 is an equidigital number, since it uses as much as digits as its factorization.

2013211300333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2013211300333 its reverse (3330031123102), we get a palindrome (5343242423435).

The spelling of 2013211300333 in words is "two trillion, thirteen billion, two hundred eleven million, three hundred thousand, three hundred thirty-three".