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20132221110000 = 243544771201101
BaseRepresentation
bin1001001001111011001011…
…11000110100011011110000
32122021121210002210211101220
410210331211320310123300
510114321242101010000
6110452340435225040
74145335130636406
oct444754570643360
978247702724356
1020132221110000
116462032a74a6a
122311914148180
13b305ca39b62c
144d85946db476
1524da42bd61a0
hex124f65e346f0

20132221110000 has 400 divisors, whose sum is σ = 67307404336128. Its totient is φ = 5180336000000.

The previous prime is 20132221109977. The next prime is 20132221110007. The reversal of 20132221110000 is 1112223102.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20132221110007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 100009450 + ... + 100210550.

Almost surely, 220132221110000 is an apocalyptic number.

20132221110000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20132221110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33653702168064).

20132221110000 is an abundant number, since it is smaller than the sum of its proper divisors (47175183226128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20132221110000 is a wasteful number, since it uses less digits than its factorization.

20132221110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201250 (or 201229 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20132221110000 its reverse (1112223102), we get a palindrome (20133333333102).

It can be divided in two parts, 201322211 and 10000, that added together give a triangular number (201332211 = T20066).

The spelling of 20132221110000 in words is "twenty trillion, one hundred thirty-two billion, two hundred twenty-one million, one hundred ten thousand".