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201323121253 is a prime number
BaseRepresentation
bin1011101101111111001…
…0110000101001100101
3201020122112222012122021
42323133302300221211
511244302204340003
6232253033103141
720354655203242
oct2733762605145
9636575865567
10201323121253
1178420720841
1233026857ab1
1315ca5491167
149a5bb005c9
1553846d02bd
hex2edfcb0a65

201323121253 has 2 divisors, whose sum is σ = 201323121254. Its totient is φ = 201323121252.

The previous prime is 201323121247. The next prime is 201323121341. The reversal of 201323121253 is 352121323102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 188952787969 + 12370333284 = 434687^2 + 111222^2 .

It is a cyclic number.

It is not a de Polignac number, because 201323121253 - 29 = 201323120741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201323121203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661560626 + 100661560627.

It is an arithmetic number, because the mean of its divisors is an integer number (100661560627).

Almost surely, 2201323121253 is an apocalyptic number.

It is an amenable number.

201323121253 is a deficient number, since it is larger than the sum of its proper divisors (1).

201323121253 is an equidigital number, since it uses as much as digits as its factorization.

201323121253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 201323121253 its reverse (352121323102), we get a palindrome (553444444355).

The spelling of 201323121253 in words is "two hundred one billion, three hundred twenty-three million, one hundred twenty-one thousand, two hundred fifty-three".