Base | Representation |
---|---|
bin | 1011101101111111001… |
… | …0110000101001100101 |
3 | 201020122112222012122021 |
4 | 2323133302300221211 |
5 | 11244302204340003 |
6 | 232253033103141 |
7 | 20354655203242 |
oct | 2733762605145 |
9 | 636575865567 |
10 | 201323121253 |
11 | 78420720841 |
12 | 33026857ab1 |
13 | 15ca5491167 |
14 | 9a5bb005c9 |
15 | 53846d02bd |
hex | 2edfcb0a65 |
201323121253 has 2 divisors, whose sum is σ = 201323121254. Its totient is φ = 201323121252.
The previous prime is 201323121247. The next prime is 201323121341. The reversal of 201323121253 is 352121323102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 188952787969 + 12370333284 = 434687^2 + 111222^2 .
It is a cyclic number.
It is not a de Polignac number, because 201323121253 - 29 = 201323120741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201323121203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661560626 + 100661560627.
It is an arithmetic number, because the mean of its divisors is an integer number (100661560627).
Almost surely, 2201323121253 is an apocalyptic number.
It is an amenable number.
201323121253 is a deficient number, since it is larger than the sum of its proper divisors (1).
201323121253 is an equidigital number, since it uses as much as digits as its factorization.
201323121253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 201323121253 its reverse (352121323102), we get a palindrome (553444444355).
The spelling of 201323121253 in words is "two hundred one billion, three hundred twenty-three million, one hundred twenty-one thousand, two hundred fifty-three".
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