20132410240037 has 2 divisors, whose sum is σ = 20132410240038. Its totient is φ = 20132410240036.

The previous prime is 20132410239983. The next prime is 20132410240039. The reversal of 20132410240037 is 73004201423102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20015682784321 + 116727455716 = 4473889^2 + 341654^2 .

It is a cyclic number.

It is not a de Polignac number, because 20132410240037 - 2⁶ = 20132410239973 is a prime.

It is a super-2 number, since 2×20132410240037² (a number of 27 digits) contains 22 as substring.

Together with 20132410240039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 20132410239991 and 20132410240009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20132410240039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066205120018 + 10066205120019.

It is an arithmetic number, because the mean of its divisors is an integer number (10066205120019).

Almost surely, 2^{20132410240037} is an apocalyptic number.

It is an amenable number.

20132410240037 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132410240037 is an equidigital number, since it uses as much as digits as its factorization.

20132410240037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 20132410240037 its reverse (73004201423102), we get a palindrome (93136611663139).

The spelling of 20132410240037 in words is "twenty trillion, one hundred thirty-two billion, four hundred ten million, two hundred forty thousand, thirty-seven".