Base | Representation |
---|---|
bin | 10010101111111111… |
… | …001011100100000001 |
3 | 1220222001202010211112 |
4 | 102233333023210001 |
5 | 312212401210132 |
6 | 13125420053105 |
7 | 1311620645141 |
oct | 225777134401 |
9 | 56861663745 |
10 | 20132444417 |
11 | 85a1270518 |
12 | 3a9a394195 |
13 | 1b8ac6ac07 |
14 | d8db20921 |
15 | 7cc6cdab2 |
hex | 4affcb901 |
20132444417 has 2 divisors, whose sum is σ = 20132444418. Its totient is φ = 20132444416.
The previous prime is 20132444401. The next prime is 20132444419. The reversal of 20132444417 is 71444423102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18467722816 + 1664721601 = 135896^2 + 40801^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132444417 - 24 = 20132444401 is a prime.
Together with 20132444419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20132444419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066222208 + 10066222209.
It is an arithmetic number, because the mean of its divisors is an integer number (10066222209).
Almost surely, 220132444417 is an apocalyptic number.
It is an amenable number.
20132444417 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132444417 is an equidigital number, since it uses as much as digits as its factorization.
20132444417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 20132444417 its reverse (71444423102), we get a palindrome (91576867519).
The spelling of 20132444417 in words is "twenty billion, one hundred thirty-two million, four hundred forty-four thousand, four hundred seventeen".
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