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201325391 is a prime number
BaseRepresentation
bin10111111111111…
…11101101001111
3112000211101111222
423333333231033
5403014403031
631551033555
74663144331
oct1377775517
9460741458
10201325391
11a3708823
125750b8bb
133292c667
141ca49451
1512a1be7b
hexbfffb4f

201325391 has 2 divisors, whose sum is σ = 201325392. Its totient is φ = 201325390.

The previous prime is 201325379. The next prime is 201325403. The reversal of 201325391 is 193523102.

It is a balanced prime because it is at equal distance from previous prime (201325379) and next prime (201325403).

It is a cyclic number.

It is not a de Polignac number, because 201325391 - 210 = 201324367 is a prime.

It is a super-2 number, since 2×2013253912 = 81063826122605762, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201325391.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201325301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100662695 + 100662696.

It is an arithmetic number, because the mean of its divisors is an integer number (100662696).

Almost surely, 2201325391 is an apocalyptic number.

201325391 is a deficient number, since it is larger than the sum of its proper divisors (1).

201325391 is an equidigital number, since it uses as much as digits as its factorization.

201325391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 26.

The square root of 201325391 is about 14188.9178939058. The cubic root of 201325391 is about 586.0925267511.

Adding to 201325391 its reverse (193523102), we get a palindrome (394848493).

The spelling of 201325391 in words is "two hundred one million, three hundred twenty-five thousand, three hundred ninety-one".