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20133100013177 is a prime number
BaseRepresentation
bin1001001001111100110100…
…10001100100011001111001
32122021201001100121201220102
410210332122101210121321
510114330042100410202
6110453003553205145
74145365662330344
oct444763221443171
978251040551812
1020133100013177
1164624440a7a28
122311b1a5607b5
13b3070a4b9598
144d863932545b
1524da94e46d02
hex124f9a464679

20133100013177 has 2 divisors, whose sum is σ = 20133100013178. Its totient is φ = 20133100013176.

The previous prime is 20133100013111. The next prime is 20133100013207. The reversal of 20133100013177 is 77131000133102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15685488961081 + 4447611052096 = 3960491^2 + 2108936^2 .

It is a cyclic number.

It is not a de Polignac number, because 20133100013177 - 210 = 20133100012153 is a prime.

It is a super-2 number, since 2×201331000131772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20133100015177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066550006588 + 10066550006589.

It is an arithmetic number, because the mean of its divisors is an integer number (10066550006589).

Almost surely, 220133100013177 is an apocalyptic number.

It is an amenable number.

20133100013177 is a deficient number, since it is larger than the sum of its proper divisors (1).

20133100013177 is an equidigital number, since it uses as much as digits as its factorization.

20133100013177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2646, while the sum is 29.

Adding to 20133100013177 its reverse (77131000133102), we get a palindrome (97264100146279).

The spelling of 20133100013177 in words is "twenty trillion, one hundred thirty-three billion, one hundred million, thirteen thousand, one hundred seventy-seven".