Base | Representation |
---|---|
bin | 1001001001111100110100… |
… | …10001100100011010010111 |
3 | 2122021201001100121201221112 |
4 | 10210332122101210122113 |
5 | 10114330042100410312 |
6 | 110453003553205235 |
7 | 4145365662330416 |
oct | 444763221443227 |
9 | 78251040551845 |
10 | 20133100013207 |
11 | 64624440a7a55 |
12 | 2311b1a56081b |
13 | b3070a4b95bc |
14 | 4d863932547d |
15 | 24da94e46d22 |
hex | 124f9a464697 |
20133100013207 has 2 divisors, whose sum is σ = 20133100013208. Its totient is φ = 20133100013206.
The previous prime is 20133100013177. The next prime is 20133100013281. The reversal of 20133100013207 is 70231000133102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20133100013207 - 216 = 20133099947671 is a prime.
It is a super-2 number, since 2×201331000132072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20133100013287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066550006603 + 10066550006604.
It is an arithmetic number, because the mean of its divisors is an integer number (10066550006604).
Almost surely, 220133100013207 is an apocalyptic number.
20133100013207 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133100013207 is an equidigital number, since it uses as much as digits as its factorization.
20133100013207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 23.
Adding to 20133100013207 its reverse (70231000133102), we get a palindrome (90364100146309).
The spelling of 20133100013207 in words is "twenty trillion, one hundred thirty-three billion, one hundred million, thirteen thousand, two hundred seven".
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