Base | Representation |
---|---|
bin | 1001001001111101001101… |
… | …10111100111010011100111 |
3 | 2122021201121002012212221111 |
4 | 10210332212313213103213 |
5 | 10114331010144010002 |
6 | 110453040542125451 |
7 | 4145404136340235 |
oct | 444764667472347 |
9 | 78251532185844 |
10 | 20133311313127 |
11 | 64625423a8791 |
12 | 2311b79280887 |
13 | b307421cc03c |
14 | 4d8659409955 |
15 | 24daa87843d7 |
hex | 124fa6de74e7 |
20133311313127 has 2 divisors, whose sum is σ = 20133311313128. Its totient is φ = 20133311313126.
The previous prime is 20133311313061. The next prime is 20133311313139. The reversal of 20133311313127 is 72131311333102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20133311313127 - 227 = 20133177095399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20133311313187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066655656563 + 10066655656564.
It is an arithmetic number, because the mean of its divisors is an integer number (10066655656564).
Almost surely, 220133311313127 is an apocalyptic number.
20133311313127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133311313127 is an equidigital number, since it uses as much as digits as its factorization.
20133311313127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 20133311313127 its reverse (72131311333102), we get a palindrome (92264622646229).
The spelling of 20133311313127 in words is "twenty trillion, one hundred thirty-three billion, three hundred eleven million, three hundred thirteen thousand, one hundred twenty-seven".
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