Base | Representation |
---|---|
bin | 1001001001111101001101… |
… | …10111100111010011110011 |
3 | 2122021201121002012212221221 |
4 | 10210332212313213103303 |
5 | 10114331010144010024 |
6 | 110453040542125511 |
7 | 4145404136340253 |
oct | 444764667472363 |
9 | 78251532185857 |
10 | 20133311313139 |
11 | 64625423a87a2 |
12 | 2311b79280897 |
13 | b307421cc04b |
14 | 4d8659409963 |
15 | 24daa87843e4 |
hex | 124fa6de74f3 |
20133311313139 has 2 divisors, whose sum is σ = 20133311313140. Its totient is φ = 20133311313138.
The previous prime is 20133311313127. The next prime is 20133311313151. The reversal of 20133311313139 is 93131311333102.
It is a balanced prime because it is at equal distance from previous prime (20133311313127) and next prime (20133311313151).
It is a cyclic number.
It is not a de Polignac number, because 20133311313139 - 29 = 20133311312627 is a prime.
It is a super-3 number, since 3×201333113131393 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (20133311310139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066655656569 + 10066655656570.
It is an arithmetic number, because the mean of its divisors is an integer number (10066655656570).
Almost surely, 220133311313139 is an apocalyptic number.
20133311313139 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133311313139 is an equidigital number, since it uses as much as digits as its factorization.
20133311313139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 34.
The spelling of 20133311313139 in words is "twenty trillion, one hundred thirty-three billion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty-nine".
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