Base | Representation |
---|---|
bin | 10010110000000101… |
… | …001100010100110111 |
3 | 1220222011201012200112 |
4 | 102300011030110313 |
5 | 312213302123112 |
6 | 13125513533235 |
7 | 1311640230644 |
oct | 226005142467 |
9 | 56864635615 |
10 | 20134020407 |
11 | 85a2147596 |
12 | 3a9aa1421b |
13 | 1b8b3a0357 |
14 | d90010dcb |
15 | 7cc8e0a22 |
hex | 4b014c537 |
20134020407 has 2 divisors, whose sum is σ = 20134020408. Its totient is φ = 20134020406.
The previous prime is 20134020391. The next prime is 20134020409. The reversal of 20134020407 is 70402043102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20134020407 - 24 = 20134020391 is a prime.
Together with 20134020409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20134020409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067010203 + 10067010204.
It is an arithmetic number, because the mean of its divisors is an integer number (10067010204).
Almost surely, 220134020407 is an apocalyptic number.
20134020407 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134020407 is an equidigital number, since it uses as much as digits as its factorization.
20134020407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 23.
Adding to 20134020407 its reverse (70402043102), we get a palindrome (90536063509).
The spelling of 20134020407 in words is "twenty billion, one hundred thirty-four million, twenty thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •