Base | Representation |
---|---|
bin | 111100000000010… |
… | …0001010100100111 |
3 | 12012022120102212112 |
4 | 1320000201110213 |
5 | 13110412334112 |
6 | 531442111235 |
7 | 100615431602 |
oct | 17000412447 |
9 | 5168512775 |
10 | 2013402407 |
11 | 943571035 |
12 | 48234b51b |
13 | 26118a793 |
14 | 151587339 |
15 | bbb5da22 |
hex | 78021527 |
2013402407 has 2 divisors, whose sum is σ = 2013402408. Its totient is φ = 2013402406.
The previous prime is 2013402379. The next prime is 2013402409. The reversal of 2013402407 is 7042043102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013402407 - 230 = 939660583 is a prime.
Together with 2013402409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013402409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006701203 + 1006701204.
It is an arithmetic number, because the mean of its divisors is an integer number (1006701204).
Almost surely, 22013402407 is an apocalyptic number.
2013402407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013402407 is an equidigital number, since it uses as much as digits as its factorization.
2013402407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 23.
The square root of 2013402407 is about 44870.9528202823. The cubic root of 2013402407 is about 1262.7291158470.
Adding to 2013402407 its reverse (7042043102), we get a palindrome (9055445509).
The spelling of 2013402407 in words is "two billion, thirteen million, four hundred two thousand, four hundred seven".
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