Base | Representation |
---|---|
bin | 111100000000010… |
… | …0001110000101111 |
3 | 12012022120112100012 |
4 | 1320000201300233 |
5 | 13110412413312 |
6 | 531442123435 |
7 | 100615440053 |
oct | 17000416057 |
9 | 5168515305 |
10 | 2013404207 |
11 | 943572421 |
12 | 48235057b |
13 | 26118b549 |
14 | 151587c63 |
15 | bbb5e322 |
hex | 78021c2f |
2013404207 has 2 divisors, whose sum is σ = 2013404208. Its totient is φ = 2013404206.
The previous prime is 2013404177. The next prime is 2013404209. The reversal of 2013404207 is 7024043102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013404207 - 218 = 2013142063 is a prime.
Together with 2013404209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013404209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006702103 + 1006702104.
It is an arithmetic number, because the mean of its divisors is an integer number (1006702104).
Almost surely, 22013404207 is an apocalyptic number.
2013404207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013404207 is an equidigital number, since it uses as much as digits as its factorization.
2013404207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 23.
The square root of 2013404207 is about 44870.9728777971. The cubic root of 2013404207 is about 1262.7294921440.
Adding to 2013404207 its reverse (7024043102), we get a palindrome (9037447309).
The spelling of 2013404207 in words is "two billion, thirteen million, four hundred four thousand, two hundred seven".
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