Search a number
-
+
20134112111341 is a prime number
BaseRepresentation
bin1001001001111110101101…
…00110011010101011101101
32122021210122220001122120121
410210333112212122223231
510114334130200030331
6110453252230044541
74145433032120014
oct444772646325355
978253586048517
1020134112111341
116462913434298
1223121614a9751
13b3083c0a1337
144d86d3901a7b
1524db03c17c11
hex124fd699aaed

20134112111341 has 2 divisors, whose sum is σ = 20134112111342. Its totient is φ = 20134112111340.

The previous prime is 20134112111317. The next prime is 20134112111357. The reversal of 20134112111341 is 14311121143102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19564432848900 + 569679262441 = 4423170^2 + 754771^2 .

It is a cyclic number.

It is not a de Polignac number, because 20134112111341 - 239 = 19584356297453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20134112111381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067056055670 + 10067056055671.

It is an arithmetic number, because the mean of its divisors is an integer number (10067056055671).

Almost surely, 220134112111341 is an apocalyptic number.

It is an amenable number.

20134112111341 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134112111341 is an equidigital number, since it uses as much as digits as its factorization.

20134112111341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 20134112111341 its reverse (14311121143102), we get a palindrome (34445233254443).

The spelling of 20134112111341 in words is "twenty trillion, one hundred thirty-four billion, one hundred twelve million, one hundred eleven thousand, three hundred forty-one".