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201341334013 is a prime number
BaseRepresentation
bin1011101110000011100…
…0001111000111111101
3201020200211020111211221
42323200320033013331
511244321340142023
6232254523313341
720355266046541
oct2734070170775
9636624214757
10201341334013
117842aa30306
123303097b851
1315ca9199c41
149a602c1a21
1553860cb85d
hex2ee0e0f1fd

201341334013 has 2 divisors, whose sum is σ = 201341334014. Its totient is φ = 201341334012.

The previous prime is 201341333981. The next prime is 201341334031. The reversal of 201341334013 is 310433143102.

Together with next prime (201341334031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101670424164 + 99670909849 = 318858^2 + 315707^2 .

It is a cyclic number.

It is not a de Polignac number, because 201341334013 - 25 = 201341333981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201341334613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670667006 + 100670667007.

It is an arithmetic number, because the mean of its divisors is an integer number (100670667007).

Almost surely, 2201341334013 is an apocalyptic number.

It is an amenable number.

201341334013 is a deficient number, since it is larger than the sum of its proper divisors (1).

201341334013 is an equidigital number, since it uses as much as digits as its factorization.

201341334013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 201341334013 its reverse (310433143102), we get a palindrome (511774477115).

The spelling of 201341334013 in words is "two hundred one billion, three hundred forty-one million, three hundred thirty-four thousand, thirteen".