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2013414014004 = 223349480757883
BaseRepresentation
bin11101010011001000110…
…100111011110000110100
321010110222021200100212120
4131103020310323300310
5230441432441422004
64140541041515540
7265315163512431
oct35231064736064
97113867610776
102013414014004
1170697a7a3078
12286268342bb0
13117b30643273
146d6421cab88
15375909603d9
hex1d4c8d3bc34

2013414014004 has 24 divisors (see below), whose sum is σ = 4711427263200. Its totient is φ = 669214971744.

The previous prime is 2013414013999. The next prime is 2013414014047. The reversal of 2013414014004 is 4004104143102.

It is a super-2 number, since 2×20134140140042 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 240374754 + ... + 240383129.

It is an arithmetic number, because the mean of its divisors is an integer number (196309469300).

Almost surely, 22013414014004 is an apocalyptic number.

It is an amenable number.

2013414014004 is an abundant number, since it is smaller than the sum of its proper divisors (2698013249196).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013414014004 is a wasteful number, since it uses less digits than its factorization.

2013414014004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 480758239 (or 480758237 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 2013414014004 its reverse (4004104143102), we get a palindrome (6017518157106).

The spelling of 2013414014004 in words is "two trillion, thirteen billion, four hundred fourteen million, fourteen thousand, four".

Divisors: 1 2 3 4 6 12 349 698 1047 1396 2094 4188 480757883 961515766 1442273649 1923031532 2884547298 5769094596 167784501167 335569002334 503353503501 671138004668 1006707007002 2013414014004