201341401421 has 2 divisors, whose sum is σ = 201341401422. Its totient is φ = 201341401420.

The previous prime is 201341401403. The next prime is 201341401423. The reversal of 201341401421 is 124104143102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123868802500 + 77472598921 = 351950^2 + 278339^2 .

It is a cyclic number.

It is not a de Polignac number, because 201341401421 - 2⁶ = 201341401357 is a prime.

Together with 201341401423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201341401423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670700710 + 100670700711.

It is an arithmetic number, because the mean of its divisors is an integer number (100670700711).

Almost surely, 2^201341401421 is an apocalyptic number.

It is an amenable number.

201341401421 is a deficient number, since it is larger than the sum of its proper divisors (1).

201341401421 is an equidigital number, since it uses as much as digits as its factorization.

201341401421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 201341401421 its reverse (124104143102), we get a palindrome (325445544523).

The spelling of 201341401421 in words is "two hundred one billion, three hundred forty-one million, four hundred one thousand, four hundred twenty-one".