Base | Representation |
---|---|
bin | 11101010011001001010… |
… | …111000010001101111111 |
3 | 21010110222220111112100012 |
4 | 131103021113002031333 |
5 | 230441442234001333 |
6 | 4140542001253435 |
7 | 265315332503564 |
oct | 35231127021577 |
9 | 7113886445305 |
10 | 2013422953343 |
11 | 70698484935a |
12 | 28626b33427b |
13 | 117b32453109 |
14 | 6d64347686b |
15 | 37591628e48 |
hex | 1d4c95c237f |
2013422953343 has 2 divisors, whose sum is σ = 2013422953344. Its totient is φ = 2013422953342.
The previous prime is 2013422953319. The next prime is 2013422953471. The reversal of 2013422953343 is 3433592243102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013422953343 - 234 = 1996243084159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2013422953343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013422955343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006711476671 + 1006711476672.
It is an arithmetic number, because the mean of its divisors is an integer number (1006711476672).
Almost surely, 22013422953343 is an apocalyptic number.
2013422953343 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013422953343 is an equidigital number, since it uses as much as digits as its factorization.
2013422953343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 2013422953343 in words is "two trillion, thirteen billion, four hundred twenty-two million, nine hundred fifty-three thousand, three hundred forty-three".
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