Base | Representation |
---|---|
bin | 11101010011001001010… |
… | …111000010001111111111 |
3 | 21010110222220111112111221 |
4 | 131103021113002033333 |
5 | 230441442234002341 |
6 | 4140542001254211 |
7 | 265315332504136 |
oct | 35231127021777 |
9 | 7113886445457 |
10 | 2013422953471 |
11 | 706984849466 |
12 | 28626b334367 |
13 | 117b324531a7 |
14 | 6d64347691d |
15 | 37591628ed1 |
hex | 1d4c95c23ff |
2013422953471 has 2 divisors, whose sum is σ = 2013422953472. Its totient is φ = 2013422953470.
The previous prime is 2013422953343. The next prime is 2013422953481. The reversal of 2013422953471 is 1743592243102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013422953471 - 27 = 2013422953343 is a prime.
It is a super-3 number, since 3×20134229534713 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013422953481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006711476735 + 1006711476736.
It is an arithmetic number, because the mean of its divisors is an integer number (1006711476736).
Almost surely, 22013422953471 is an apocalyptic number.
2013422953471 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013422953471 is an equidigital number, since it uses as much as digits as its factorization.
2013422953471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 2013422953471 in words is "two trillion, thirteen billion, four hundred twenty-two million, nine hundred fifty-three thousand, four hundred seventy-one".
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