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201343400053 is a prime number
BaseRepresentation
bin1011101110000100000…
…0000111100001110101
3201020200222010110220221
42323201000013201311
511244322402300203
6232255035454341
720355322443145
oct2734100074165
9636628113827
10201343400053
1178431111584
12330315b73b1
1315ca9741453
149a6069c925
155386388abd
hex2ee1007875

201343400053 has 2 divisors, whose sum is σ = 201343400054. Its totient is φ = 201343400052.

The previous prime is 201343400017. The next prime is 201343400099. The reversal of 201343400053 is 350004343102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 174851931409 + 26491468644 = 418153^2 + 162762^2 .

It is a cyclic number.

It is not a de Polignac number, because 201343400053 - 217 = 201343268981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201343406053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671700026 + 100671700027.

It is an arithmetic number, because the mean of its divisors is an integer number (100671700027).

Almost surely, 2201343400053 is an apocalyptic number.

It is an amenable number.

201343400053 is a deficient number, since it is larger than the sum of its proper divisors (1).

201343400053 is an equidigital number, since it uses as much as digits as its factorization.

201343400053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 201343400053 its reverse (350004343102), we get a palindrome (551347743155).

The spelling of 201343400053 in words is "two hundred one billion, three hundred forty-three million, four hundred thousand, fifty-three".