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20135034339997 is a prime number
BaseRepresentation
bin1001001010000000011011…
…00100011100001010011101
32122021220001011101201110111
410211000031210130022131
510114343022242334442
6110453523532410021
74145464630666213
oct445001544341235
978256034351414
1020135034339997
116463246a69335
12231237a316911
13b3095817b675
144d87801a6cb3
1524db59b85b17
hex12500d91c29d

20135034339997 has 2 divisors, whose sum is σ = 20135034339998. Its totient is φ = 20135034339996.

The previous prime is 20135034339919. The next prime is 20135034340013. The reversal of 20135034339997 is 79993343053102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15589657243876 + 4545377096121 = 3948374^2 + 2131989^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20135034339997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20135034379997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067517169998 + 10067517169999.

It is an arithmetic number, because the mean of its divisors is an integer number (10067517169999).

Almost surely, 220135034339997 is an apocalyptic number.

It is an amenable number.

20135034339997 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135034339997 is an equidigital number, since it uses as much as digits as its factorization.

20135034339997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16533720, while the sum is 58.

The spelling of 20135034339997 in words is "twenty trillion, one hundred thirty-five billion, thirty-four million, three hundred thirty-nine thousand, nine hundred ninety-seven".