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20135034340013 is a prime number
BaseRepresentation
bin1001001010000000011011…
…00100011100001010101101
32122021220001011101201111002
410211000031210130022231
510114343022242340023
6110453523532410045
74145464630666235
oct445001544341255
978256034351432
1020135034340013
116463246a6934a
12231237a316925
13b3095817b688
144d87801a6cc5
1524db59b85b28
hex12500d91c2ad

20135034340013 has 2 divisors, whose sum is σ = 20135034340014. Its totient is φ = 20135034340012.

The previous prime is 20135034339997. The next prime is 20135034340051. The reversal of 20135034340013 is 31004343053102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13577655235369 + 6557379104644 = 3684787^2 + 2560738^2 .

It is a cyclic number.

It is not a de Polignac number, because 20135034340013 - 24 = 20135034339997 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20135034346013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067517170006 + 10067517170007.

It is an arithmetic number, because the mean of its divisors is an integer number (10067517170007).

Almost surely, 220135034340013 is an apocalyptic number.

It is an amenable number.

20135034340013 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135034340013 is an equidigital number, since it uses as much as digits as its factorization.

20135034340013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 20135034340013 its reverse (31004343053102), we get a palindrome (51139377393115).

The spelling of 20135034340013 in words is "twenty trillion, one hundred thirty-five billion, thirty-four million, three hundred forty thousand, thirteen".