Base | Representation |
---|---|
bin | 11101010011010100000… |
… | …110000001101000100011 |
3 | 21010111110110101002002220 |
4 | 131103110012001220203 |
5 | 230442324334401000 |
6 | 4141011513242123 |
7 | 265322650320063 |
oct | 35232406015043 |
9 | 7114413332086 |
10 | 2013603043875 |
11 | 706a67473005 |
12 | 2862bb703343 |
13 | 117b60859267 |
14 | 6d65d3553a3 |
15 | 375a234e1a0 |
hex | 1d4d4181a23 |
2013603043875 has 64 divisors (see below), whose sum is σ = 3592640563200. Its totient is φ = 997955212800.
The previous prime is 2013603043873. The next prime is 2013603043891. The reversal of 2013603043875 is 5783403063102.
It is not a de Polignac number, because 2013603043875 - 21 = 2013603043873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2013603043873) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1495485 + ... + 2502734.
It is an arithmetic number, because the mean of its divisors is an integer number (56135008800).
Almost surely, 22013603043875 is an apocalyptic number.
2013603043875 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2013603043875 is a deficient number, since it is larger than the sum of its proper divisors (1579037519325).
2013603043875 is a wasteful number, since it uses less digits than its factorization.
2013603043875 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3998333 (or 3998323 counting only the distinct ones).
The product of its (nonzero) digits is 362880, while the sum is 42.
The spelling of 2013603043875 in words is "two trillion, thirteen billion, six hundred three million, forty-three thousand, eight hundred seventy-five".
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