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20136335512493 is a prime number
BaseRepresentation
bin1001001010000010110110…
…01000000001001110101101
32122022000101211210010120102
410211001123020001032231
510114403203342344433
6110454301013200445
74145542110532064
oct445013310011655
978260354703512
1020136335512493
116463854497502
122312682030125
13b30b04907215
144d8864d111db
1524dbd40084e8
hex12505b2013ad

20136335512493 has 2 divisors, whose sum is σ = 20136335512494. Its totient is φ = 20136335512492.

The previous prime is 20136335512459. The next prime is 20136335512529. The reversal of 20136335512493 is 39421553363102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14223593730724 + 5912741781769 = 3771418^2 + 2431613^2 .

It is a cyclic number.

It is not a de Polignac number, because 20136335512493 - 230 = 20135261770669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20136335512793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10068167756246 + 10068167756247.

It is an arithmetic number, because the mean of its divisors is an integer number (10068167756247).

Almost surely, 220136335512493 is an apocalyptic number.

It is an amenable number.

20136335512493 is a deficient number, since it is larger than the sum of its proper divisors (1).

20136335512493 is an equidigital number, since it uses as much as digits as its factorization.

20136335512493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1749600, while the sum is 47.

Adding to 20136335512493 its reverse (39421553363102), we get a palindrome (59557888875595).

The spelling of 20136335512493 in words is "twenty trillion, one hundred thirty-six billion, three hundred thirty-five million, five hundred twelve thousand, four hundred ninety-three".