Base | Representation |
---|---|
bin | 1001001010000010110110… |
… | …01000000001001110101101 |
3 | 2122022000101211210010120102 |
4 | 10211001123020001032231 |
5 | 10114403203342344433 |
6 | 110454301013200445 |
7 | 4145542110532064 |
oct | 445013310011655 |
9 | 78260354703512 |
10 | 20136335512493 |
11 | 6463854497502 |
12 | 2312682030125 |
13 | b30b04907215 |
14 | 4d8864d111db |
15 | 24dbd40084e8 |
hex | 12505b2013ad |
20136335512493 has 2 divisors, whose sum is σ = 20136335512494. Its totient is φ = 20136335512492.
The previous prime is 20136335512459. The next prime is 20136335512529. The reversal of 20136335512493 is 39421553363102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14223593730724 + 5912741781769 = 3771418^2 + 2431613^2 .
It is a cyclic number.
It is not a de Polignac number, because 20136335512493 - 230 = 20135261770669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20136335512793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10068167756246 + 10068167756247.
It is an arithmetic number, because the mean of its divisors is an integer number (10068167756247).
Almost surely, 220136335512493 is an apocalyptic number.
It is an amenable number.
20136335512493 is a deficient number, since it is larger than the sum of its proper divisors (1).
20136335512493 is an equidigital number, since it uses as much as digits as its factorization.
20136335512493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 47.
Adding to 20136335512493 its reverse (39421553363102), we get a palindrome (59557888875595).
The spelling of 20136335512493 in words is "twenty trillion, one hundred thirty-six billion, three hundred thirty-five million, five hundred twelve thousand, four hundred ninety-three".
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