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20140161397 is a prime number
BaseRepresentation
bin10010110000011100…
…100111100101110101
31220222121021012112121
4102300130213211311
5312221340131042
613130253315541
71312043355466
oct226034474565
956877235477
1020140161397
1185a5661394
123aa0a95bb1
131b8c740585
14d90b6cd6d
157cd205367
hex4b0727975

20140161397 has 2 divisors, whose sum is σ = 20140161398. Its totient is φ = 20140161396.

The previous prime is 20140161389. The next prime is 20140161427. The reversal of 20140161397 is 79316104102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14853271876 + 5286889521 = 121874^2 + 72711^2 .

It is a cyclic number.

It is not a de Polignac number, because 20140161397 - 23 = 20140161389 is a prime.

It is a super-2 number, since 2×201401613972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20140161317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10070080698 + 10070080699.

It is an arithmetic number, because the mean of its divisors is an integer number (10070080699).

Almost surely, 220140161397 is an apocalyptic number.

It is an amenable number.

20140161397 is a deficient number, since it is larger than the sum of its proper divisors (1).

20140161397 is an equidigital number, since it uses as much as digits as its factorization.

20140161397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 34.

Adding to 20140161397 its reverse (79316104102), we get a palindrome (99456265499).

The spelling of 20140161397 in words is "twenty billion, one hundred forty million, one hundred sixty-one thousand, three hundred ninety-seven".