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201414233131 is a prime number
BaseRepresentation
bin1011101110010100111…
…0010100110000101011
3201020212220102011122021
42323211032110300223
511244444020430011
6232310050005311
720360142506446
oct2734516246053
9636786364567
10201414233131
11784680a1511
1233051276837
1315cbb312207
149a69c5a65d
15538c6cb471
hex2ee5394c2b

201414233131 has 2 divisors, whose sum is σ = 201414233132. Its totient is φ = 201414233130.

The previous prime is 201414233129. The next prime is 201414233161. The reversal of 201414233131 is 131332414102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201414233131 - 21 = 201414233129 is a prime.

It is a super-2 number, since 2×2014142331312 (a number of 23 digits) contains 22 as substring.

Together with 201414233129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 201414233096 and 201414233105.

It is not a weakly prime, because it can be changed into another prime (201414233161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100707116565 + 100707116566.

It is an arithmetic number, because the mean of its divisors is an integer number (100707116566).

Almost surely, 2201414233131 is an apocalyptic number.

201414233131 is a deficient number, since it is larger than the sum of its proper divisors (1).

201414233131 is an equidigital number, since it uses as much as digits as its factorization.

201414233131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 201414233131 its reverse (131332414102), we get a palindrome (332746647233).

The spelling of 201414233131 in words is "two hundred one billion, four hundred fourteen million, two hundred thirty-three thousand, one hundred thirty-one".