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2014265131 is a prime number
BaseRepresentation
bin111100000001111…
…0011111100101011
312012101012021022021
41320003303330223
513111122441011
6531512405311
7100625654044
oct17003637453
95171167267
102014265131
1194400022a
124826a6837
13261400378
1415172d8cb
15bbc7e471
hex780f3f2b

2014265131 has 2 divisors, whose sum is σ = 2014265132. Its totient is φ = 2014265130.

The previous prime is 2014265081. The next prime is 2014265147. The reversal of 2014265131 is 1315624102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2014265131 - 27 = 2014265003 is a prime.

It is a super-2 number, since 2×20142651312 = 8114528035924894322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2014265096 and 2014265105.

It is not a weakly prime, because it can be changed into another prime (2014265171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007132565 + 1007132566.

It is an arithmetic number, because the mean of its divisors is an integer number (1007132566).

Almost surely, 22014265131 is an apocalyptic number.

2014265131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014265131 is an equidigital number, since it uses as much as digits as its factorization.

2014265131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 2014265131 is about 44880.5651813789. The cubic root of 2014265131 is about 1262.9094459439.

Adding to 2014265131 its reverse (1315624102), we get a palindrome (3329889233).

The spelling of 2014265131 in words is "two billion, fourteen million, two hundred sixty-five thousand, one hundred thirty-one".