Base | Representation |
---|---|
bin | 111100000001111… |
… | …0011111100101011 |
3 | 12012101012021022021 |
4 | 1320003303330223 |
5 | 13111122441011 |
6 | 531512405311 |
7 | 100625654044 |
oct | 17003637453 |
9 | 5171167267 |
10 | 2014265131 |
11 | 94400022a |
12 | 4826a6837 |
13 | 261400378 |
14 | 15172d8cb |
15 | bbc7e471 |
hex | 780f3f2b |
2014265131 has 2 divisors, whose sum is σ = 2014265132. Its totient is φ = 2014265130.
The previous prime is 2014265081. The next prime is 2014265147. The reversal of 2014265131 is 1315624102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014265131 - 27 = 2014265003 is a prime.
It is a super-2 number, since 2×20142651312 = 8114528035924894322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2014265096 and 2014265105.
It is not a weakly prime, because it can be changed into another prime (2014265171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007132565 + 1007132566.
It is an arithmetic number, because the mean of its divisors is an integer number (1007132566).
Almost surely, 22014265131 is an apocalyptic number.
2014265131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014265131 is an equidigital number, since it uses as much as digits as its factorization.
2014265131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 2014265131 is about 44880.5651813789. The cubic root of 2014265131 is about 1262.9094459439.
Adding to 2014265131 its reverse (1315624102), we get a palindrome (3329889233).
The spelling of 2014265131 in words is "two billion, fourteen million, two hundred sixty-five thousand, one hundred thirty-one".
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