Base | Representation |
---|---|
bin | 11101010011111111011… |
… | …100101101110000010011 |
3 | 21010120100011001012122222 |
4 | 131103333130231300103 |
5 | 231000322041141201 |
6 | 4141212015251255 |
7 | 265346661666026 |
oct | 35237734556023 |
9 | 7116304035588 |
10 | 2014330412051 |
11 | 707300005531 |
12 | 286483219b2b |
13 | 117c4845b729 |
14 | 6d6cbbb51bd |
15 | 375e612a91b |
hex | 1d4ff72dc13 |
2014330412051 has 2 divisors, whose sum is σ = 2014330412052. Its totient is φ = 2014330412050.
The previous prime is 2014330412027. The next prime is 2014330412053. The reversal of 2014330412051 is 1502140334102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014330412051 - 26 = 2014330411987 is a prime.
Together with 2014330412053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2014330412051.
It is not a weakly prime, because it can be changed into another prime (2014330412053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007165206025 + 1007165206026.
It is an arithmetic number, because the mean of its divisors is an integer number (1007165206026).
Almost surely, 22014330412051 is an apocalyptic number.
2014330412051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014330412051 is an equidigital number, since it uses as much as digits as its factorization.
2014330412051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 2014330412051 its reverse (1502140334102), we get a palindrome (3516470746153).
The spelling of 2014330412051 in words is "two trillion, fourteen billion, three hundred thirty million, four hundred twelve thousand, fifty-one".
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