Base | Representation |
---|---|
bin | 1011101110011011100… |
… | …0101101011001111101 |
3 | 201020221211220001001221 |
4 | 2323212320231121331 |
5 | 11300023140340331 |
6 | 232312523433341 |
7 | 20360631531256 |
oct | 2734670553175 |
9 | 636854801057 |
10 | 201442121341 |
11 | 7848190a31a |
12 | 3305a685851 |
13 | 15cc4027c06 |
14 | 9a6d839b2d |
15 | 538ed89711 |
hex | 2ee6e2d67d |
201442121341 has 2 divisors, whose sum is σ = 201442121342. Its totient is φ = 201442121340.
The previous prime is 201442121281. The next prime is 201442121389. The reversal of 201442121341 is 143121244102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 150560296441 + 50881824900 = 388021^2 + 225570^2 .
It is a cyclic number.
It is not a de Polignac number, because 201442121341 - 213 = 201442113149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201442124341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100721060670 + 100721060671.
It is an arithmetic number, because the mean of its divisors is an integer number (100721060671).
Almost surely, 2201442121341 is an apocalyptic number.
It is an amenable number.
201442121341 is a deficient number, since it is larger than the sum of its proper divisors (1).
201442121341 is an equidigital number, since it uses as much as digits as its factorization.
201442121341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 201442121341 its reverse (143121244102), we get a palindrome (344563365443).
The spelling of 201442121341 in words is "two hundred one billion, four hundred forty-two million, one hundred twenty-one thousand, three hundred forty-one".
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