Base | Representation |
---|---|
bin | 11101010100101000000… |
… | …000111101111110110101 |
3 | 21010122002120200212202211 |
4 | 131110220000331332311 |
5 | 231003220304114331 |
6 | 4141403330533421 |
7 | 265402564636066 |
oct | 35245000757665 |
9 | 7118076625684 |
10 | 2015011004341 |
11 | 70761a1a95a5 |
12 | 286633137271 |
13 | 11802646416a |
14 | 6d75433a56d |
15 | 37635c678b1 |
hex | 1d52803dfb5 |
2015011004341 has 2 divisors, whose sum is σ = 2015011004342. Its totient is φ = 2015011004340.
The previous prime is 2015011004339. The next prime is 2015011004353. The reversal of 2015011004341 is 1434001105102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1854894183025 + 160116821316 = 1361945^2 + 400146^2 .
It is a cyclic number.
It is not a de Polignac number, because 2015011004341 - 21 = 2015011004339 is a prime.
Together with 2015011004339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2015011002341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007505502170 + 1007505502171.
It is an arithmetic number, because the mean of its divisors is an integer number (1007505502171).
Almost surely, 22015011004341 is an apocalyptic number.
It is an amenable number.
2015011004341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2015011004341 is an equidigital number, since it uses as much as digits as its factorization.
2015011004341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 2015011004341 its reverse (1434001105102), we get a palindrome (3449012109443).
The spelling of 2015011004341 in words is "two trillion, fifteen billion, eleven million, four thousand, three hundred forty-one".
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