Search a number
-
+
20150310552000 = 263533011278843
BaseRepresentation
bin1001001010011100111000…
…00110100100000111000000
32122100100110210021200210020
410211032130012210013000
510120120314000131000
6110504531434533440
74146545323441356
oct445163406440700
978310423250706
1020150310552000
116469775a97532
122315322297280
13b32220cb6b75
144d93ccd6b7d6
1524e250d5aba0
hex12539c1a41c0

20150310552000 has 224 divisors, whose sum is σ = 66558661887744. Its totient is φ = 5371612288000.

The previous prime is 20150310551977. The next prime is 20150310552023. The reversal of 20150310552000 is 25501305102.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (20150310551977) and next prime (20150310552023).

It is a super-3 number, since 3×201503105520003 (a number of 41 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 72124579 + ... + 72403421.

Almost surely, 220150310552000 is an apocalyptic number.

20150310552000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20150310552000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33279330943872).

20150310552000 is an abundant number, since it is smaller than the sum of its proper divisors (46408351335744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20150310552000 is a wasteful number, since it uses less digits than its factorization.

20150310552000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 281884 (or 281864 counting only the distinct ones).

The product of its (nonzero) digits is 1500, while the sum is 24.

Adding to 20150310552000 its reverse (25501305102), we get a palindrome (20175811857102).

The spelling of 20150310552000 in words is "twenty trillion, one hundred fifty billion, three hundred ten million, five hundred fifty-two thousand".