Base | Representation |
---|---|
bin | 1011101110101100010… |
… | …0110110100000101111 |
3 | 201021010202011020102021 |
4 | 2323223010312200233 |
5 | 11300144134210411 |
6 | 232323514211011 |
7 | 20362444152013 |
oct | 2735304664057 |
9 | 637122136367 |
10 | 201512413231 |
11 | 7850855a698 |
12 | 3307a123a67 |
13 | 1600576954c |
14 | 9a78cd6543 |
15 | 5396121a71 |
hex | 2eeb13682f |
201512413231 has 2 divisors, whose sum is σ = 201512413232. Its totient is φ = 201512413230.
The previous prime is 201512413183. The next prime is 201512413259. The reversal of 201512413231 is 132314215102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201512413231 - 29 = 201512412719 is a prime.
It is a super-2 number, since 2×2015124132312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201512413196 and 201512413205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201512413631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100756206615 + 100756206616.
It is an arithmetic number, because the mean of its divisors is an integer number (100756206616).
Almost surely, 2201512413231 is an apocalyptic number.
201512413231 is a deficient number, since it is larger than the sum of its proper divisors (1).
201512413231 is an equidigital number, since it uses as much as digits as its factorization.
201512413231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 201512413231 its reverse (132314215102), we get a palindrome (333826628333).
The spelling of 201512413231 in words is "two hundred one billion, five hundred twelve million, four hundred thirteen thousand, two hundred thirty-one".
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