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2015135645183 is a prime number
BaseRepresentation
bin11101010100101111011…
…100011011110111111111
321010122102021020021212022
4131110233130123313333
5231003444211121213
64141423542230355
7265405640236343
oct35245734336777
97118367207768
102015135645183
117076835a0061
12286668a253bb
1311804622453b
146d766b03623
1537641b88308
hex1d52f71bdff

2015135645183 has 2 divisors, whose sum is σ = 2015135645184. Its totient is φ = 2015135645182.

The previous prime is 2015135645071. The next prime is 2015135645227. The reversal of 2015135645183 is 3815465315102.

It is an a-pointer prime, because the next prime (2015135645227) can be obtained adding 2015135645183 to its sum of digits (44).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2015135645183 - 28 = 2015135644927 is a prime.

It is a super-2 number, since 2×20151356451832 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2015135645483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007567822591 + 1007567822592.

It is an arithmetic number, because the mean of its divisors is an integer number (1007567822592).

Almost surely, 22015135645183 is an apocalyptic number.

2015135645183 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015135645183 is an equidigital number, since it uses as much as digits as its factorization.

2015135645183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 44.

The spelling of 2015135645183 in words is "two trillion, fifteen billion, one hundred thirty-five million, six hundred forty-five thousand, one hundred eighty-three".