Base | Representation |
---|---|
bin | 10010110001010011… |
… | …111100000011101101 |
3 | 1221000121112222012112 |
4 | 102301103330003231 |
5 | 312234043210044 |
6 | 13131532213405 |
7 | 1312310544605 |
oct | 226123740355 |
9 | 57017488175 |
10 | 20154663149 |
11 | 8602866805 |
12 | 3aa590a265 |
13 | 1b9274a1aa |
14 | d92a65c05 |
15 | 7ce61c09e |
hex | 4b14fc0ed |
20154663149 has 2 divisors, whose sum is σ = 20154663150. Its totient is φ = 20154663148.
The previous prime is 20154663131. The next prime is 20154663167. The reversal of 20154663149 is 94136645102.
It is a balanced prime because it is at equal distance from previous prime (20154663131) and next prime (20154663167).
It can be written as a sum of positive squares in only one way, i.e., 18122005924 + 2032657225 = 134618^2 + 45085^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20154663149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20154663119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077331574 + 10077331575.
It is an arithmetic number, because the mean of its divisors is an integer number (10077331575).
Almost surely, 220154663149 is an apocalyptic number.
It is an amenable number.
20154663149 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154663149 is an equidigital number, since it uses as much as digits as its factorization.
20154663149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 20154663149 in words is "twenty billion, one hundred fifty-four million, six hundred sixty-three thousand, one hundred forty-nine".
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