Base | Representation |
---|---|
bin | 10010110001010101… |
… | …001110011011011111 |
3 | 1221000122012010000121 |
4 | 102301111032123133 |
5 | 312234140004133 |
6 | 13131543335411 |
7 | 1312313451346 |
oct | 226125163337 |
9 | 57018163017 |
10 | 20155000543 |
11 | 8602a77247 |
12 | 3aa5a51567 |
13 | 1b92837932 |
14 | d92b12b5d |
15 | 7ce68702d |
hex | 4b154e6df |
20155000543 has 2 divisors, whose sum is σ = 20155000544. Its totient is φ = 20155000542.
The previous prime is 20155000511. The next prime is 20155000583. The reversal of 20155000543 is 34500055102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20155000543 - 25 = 20155000511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20155000583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077500271 + 10077500272.
It is an arithmetic number, because the mean of its divisors is an integer number (10077500272).
Almost surely, 220155000543 is an apocalyptic number.
20155000543 is a deficient number, since it is larger than the sum of its proper divisors (1).
20155000543 is an equidigital number, since it uses as much as digits as its factorization.
20155000543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 25.
Adding to 20155000543 its reverse (34500055102), we get a palindrome (54655055645).
The spelling of 20155000543 in words is "twenty billion, one hundred fifty-five million, five hundred forty-three", and thus it is an aban number.
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