Base | Representation |
---|---|
bin | 10010110001110000… |
… | …100101001001101101 |
3 | 1221001010200102201122 |
4 | 102301300211021231 |
5 | 312243003442001 |
6 | 13132401150325 |
7 | 1312431426053 |
oct | 226160451155 |
9 | 57033612648 |
10 | 20162171501 |
11 | 860702495a |
12 | 3aa832b3a5 |
13 | 1b941788c4 |
14 | d93a5c1d3 |
15 | 7d0101b1b |
hex | 4b1c2526d |
20162171501 has 2 divisors, whose sum is σ = 20162171502. Its totient is φ = 20162171500.
The previous prime is 20162171429. The next prime is 20162171503. The reversal of 20162171501 is 10517126102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17206618276 + 2955553225 = 131174^2 + 54365^2 .
It is a cyclic number.
It is not a de Polignac number, because 20162171501 - 218 = 20161909357 is a prime.
Together with 20162171503, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20162171503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081085750 + 10081085751.
It is an arithmetic number, because the mean of its divisors is an integer number (10081085751).
Almost surely, 220162171501 is an apocalyptic number.
It is an amenable number.
20162171501 is a deficient number, since it is larger than the sum of its proper divisors (1).
20162171501 is an equidigital number, since it uses as much as digits as its factorization.
20162171501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 26.
Adding to 20162171501 its reverse (10517126102), we get a palindrome (30679297603).
The spelling of 20162171501 in words is "twenty billion, one hundred sixty-two million, one hundred seventy-one thousand, five hundred one".
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