Base | Representation |
---|---|
bin | 10010110001110010… |
… | …000011001000001111 |
3 | 1221001011101222202022 |
4 | 102301302003020033 |
5 | 312243103301211 |
6 | 13132413320355 |
7 | 1312434621233 |
oct | 226162031017 |
9 | 57034358668 |
10 | 20162556431 |
11 | 8607268086 |
12 | 3aa84960bb |
13 | 1b94281b84 |
14 | d93b1c5c3 |
15 | 7d017abdb |
hex | 4b1c8320f |
20162556431 has 2 divisors, whose sum is σ = 20162556432. Its totient is φ = 20162556430.
The previous prime is 20162556389. The next prime is 20162556473. The reversal of 20162556431 is 13465526102.
It is a balanced prime because it is at equal distance from previous prime (20162556389) and next prime (20162556473).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20162556431 is a prime.
It is a super-2 number, since 2×201625564312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20162556391 and 20162556400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20162556031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081278215 + 10081278216.
It is an arithmetic number, because the mean of its divisors is an integer number (10081278216).
Almost surely, 220162556431 is an apocalyptic number.
20162556431 is a deficient number, since it is larger than the sum of its proper divisors (1).
20162556431 is an equidigital number, since it uses as much as digits as its factorization.
20162556431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 20162556431 in words is "twenty billion, one hundred sixty-two million, five hundred fifty-six thousand, four hundred thirty-one".
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