Base | Representation |
---|---|
bin | 1001001011111011011110… |
… | …11000111011101100101111 |
3 | 2122112012120101120222112122 |
4 | 10211331233120323230233 |
5 | 10121433323100000142 |
6 | 110544131321023155 |
7 | 4153324042562051 |
oct | 445755730735457 |
9 | 78465511528478 |
10 | 20201100000047 |
11 | 648926934358a |
12 | 2323137624abb |
13 | b36c564838c5 |
14 | 4dba4a47b8d1 |
15 | 250724b911d2 |
hex | 125f6f63bb2f |
20201100000047 has 2 divisors, whose sum is σ = 20201100000048. Its totient is φ = 20201100000046.
The previous prime is 20201099999897. The next prime is 20201100000083. The reversal of 20201100000047 is 74000000110202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20201100000047 - 232 = 20196805032751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20201099999980 and 20201100000034.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20201100000247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10100550000023 + 10100550000024.
It is an arithmetic number, because the mean of its divisors is an integer number (10100550000024).
Almost surely, 220201100000047 is an apocalyptic number.
20201100000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
20201100000047 is an equidigital number, since it uses as much as digits as its factorization.
20201100000047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 20201100000047 its reverse (74000000110202), we get a palindrome (94201100110249).
The spelling of 20201100000047 in words is "twenty trillion, two hundred one billion, one hundred million, forty-seven", and thus it is an aban number.
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